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[Guide] Numerical Analysis of TOS {WIP}
#11
(03-08-2015, 06:27 PM)agnesi Wrote:
Quote:If you activates it, just multiply them to the damage accordingly.
Next, the score itself also contributes as damage multiplier. The formula is
1 + Score/10000

I don't know if you saw the DC guide, but we figured out that the damage boost is lowered for scores over 5000.

For scores less than or equal to 5000:

Damage Boost = 1 + Score/10000

For scores over 5000:

Damage Boost = 1.5 + (Score-5000)*0.25/10000

erm, that's what i get from chinese wiki, i shall try to verify it

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#12
After testing at 1st seal Saruman, it is indeed as you said, DC's score effect reduces after 5000

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#13
Great job ~
After playing for close to a year, I never have the actual break down of numbers and just play by gut feeling.
This will give me a more accurate analysis in those tough GM/SM to see if I can to burst down a mini/boss with just the board, convert, active burst, etc.

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#14
is this the TOS bible?
I'm from Spain, so excuse my language mistakes, "beaches" Big Grin
[Image: 345o7c0.png] 


Regular allies> all max PR nidoggh, all max Yog-sothoth, all max Pr giemsa, all max PR artemis, all max beelzebub.

I ally the most common ally in SM and farmable weeklys.
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#15
Hey Arigato, very nice guide you made indeed!

Just a minor info I'd like to point out for WuKong leader skill, as below.

For normal WuKong leader skill, the equation is HP^3 x 60%,
but for WuKong amelII, the equation is HP^1/3 x 80%.

What really makes WuKong OP is NOT because of the percentage increase from 60% to 80%, instead it's because MH changed the formula altogether.

One IRL example I could provide is Tyr's double hit in Eternal Transmigration, video here.
I took Tyr's double hit and only to receive a mere 2711 damage, both hit counted.
HP RemainingEffective ReductionDamage Received
1578896%1220
1456895.11%1491
13077

Just to show how much difference the 2 formula is,
Dual WuKong, HP 16000, Damage 100 000, double strike

HP^3 x 80%
HP RemainingEffective ReductionDamage Received
1600096%4000
1200056.11%43890
Dead

HP^1/3 x 80%
HP RemainingEffective ReductionDamage Received
1600096%4000
1478092.54%7461
4538

Yes, dual Wukong amelII can bloody tank double hit of 100k damage!!!

(ps : expect to have some margin of difference for numbers in table)
(pps : please let me know ASAP if I've embarrassed myself by giving out an overwhelming wrong info)
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#16
(03-10-2015, 06:59 PM)azure86 Wrote: Hey Arigato, very nice guide you made indeed!

Just a minor info I'd like to point out for WuKong leader skill, as below.

For normal WuKong leader skill, the equation is HP^3 x 60%,
but for WuKong amelII, the equation is HP^1/3 x 80%.

What really makes WuKong OP is NOT because of the percentage increase from 60% to 80%, instead it's because MH changed the formula altogether.

One IRL example I could provide is Tyr's double hit in Eternal Transmigration, video here.
I took Tyr's double hit and only to receive a mere 2711 damage, both hit counted.

HP RemainingEffective ReductionDamage Received
1578896%1220
1456895.11%1491
13077

Just to show how much difference the 2 formula is,
Dual WuKong, HP 16000, Damage 100 000, double strike


HP^3 x 80%
HP RemainingEffective ReductionDamage Received
1600096%4000
1200056.11%43890
Dead

HP^1/3 x 80%
HP RemainingEffective ReductionDamage Received
1600096%4000
1478092.54%7461
4538

Yes, dual Wukong amelII can bloody tank double hit of 100k damage!!!

(ps : expect to have some margin of difference for numbers in table)
(pps : please let me know ASAP if I've embarrassed myself by giving out an overwhelming wrong info)

that's some important information. I have verify the information from your video and another, the data totally match. Seriously i am not sure what MH is doing, up to 80% is OP enough but change the formula from cube to cube root is even more crazy...
I will update the formula now.
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#17
I think you have got the enchanted runes bonus wrong. Your unenchanted runes damage calculation is correct, but I think the following explanation makes the enchanted runes bonus clearer:

For unenchanted runes,
Every set of 3 runes = 1, e.g. 2* sets of 3 runes = 2
For each rune above 3 you add 0.25, e.g. set of 4 runes = 1.25, set of 5 runes = 1.5

For each enchanted rune you add 0.15 to the above calculation, so
Set of 3 runes, all enchanted = 1 + 3*0.15 = 1.45
Set of 4 runes, 3 enchanted = 1.25 + 3*0.15 = 1.7

For dual Norse, you get a bonus 0.1 for each enchanted rune, i.e. 0.25 for each enchanted rune
Set of 3 runes, all enchanted = 1 + 3*0.25 = 1.75
Set of 4 runes, 3 enchanted = 1.25 + 3*0.25 = 2
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#18
(03-10-2015, 09:27 PM)killerwombat Wrote: I think you have got the enchanted runes bonus wrong.  Your unenchanted runes damage calculation is correct, but I think the following explanation makes the enchanted runes bonus clearer:

For unenchanted runes,
Every set of 3 runes = 1, e.g. 2* sets of 3 runes = 2
For each rune above 3 you add 0.25, e.g. set of 4 runes = 1.25, set of 5 runes = 1.5

For each enchanted rune you add 0.15 to the above calculation, so
Set of 3 runes, all enchanted = 1 + 3*0.15 = 1.45
Set of 4 runes, 3 enchanted = 1.25 + 3*0.15 = 1.7

For dual Norse, you get a bonus 0.1 for each enchanted rune, i.e. 0.25 for each enchanted rune
Set of 3 runes, all enchanted = 1 + 3*0.25 = 1.75
Set of 4 runes, 3 enchanted = 1.25 + 3*0.25 = 2

just change 0.1 to 0.15, thanks for pointing it out. I know for dual norse enchanted rune = 2 non-enchanted, but seems like i remember the default one wrongly.
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#19
Wink 
(03-10-2015, 08:48 AM)agatio Wrote: is this the TOS bible?

Just saw this thread today. Was exactly going to post the same thing. 

This is TOS BIBLE. It should be in-game guide \o/ 
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#20
This thread inspired me to continue working on a damage calculator.  Based on the information in this thread, I went ahead and updated this spreadsheet model -- it's clunky but at least it seems to work on a basic level.

Unfortunately, it's not very automated yet...all the yellow highlighted cells require some input.

I hope to continue to learn more useful (and updated) information from this thread.  Thanks again for the inspiration.
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